JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Elasticity & SHM

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The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement ( x ) starting from mean position to extreme position (A) is given by

(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)
✓ Correct

Answer: (D)

Solution

In simple harmonic motion the kinetic energy is

K E = \frac{1}{2} m ω^{2} (A^{2} - x^{2})

. It is greatest at the mean position,

K E_{ma x} = \frac{1}{2} m ω^{2} A^{2}

x = 0

, and falls to zero at the extreme position

x = A

. The graph is a downward curve that begins at its maximum on the vertical axis and meets the horizontal axis at

x = A

. The representation showing kinetic energy largest at the mean position and decreasing to zero at the extreme is the correct one.

JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Single correct option

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