The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of $176 \mathrm{rad} / \mathrm{s}$. The frequency of this simple harmonic oscillator is___ Hz. $\left[\right.$ take $\left.\pi=\frac{22}{7}\right]$

JEE Main · 2026 · 21 Jan 2026 · Shift 2 · Elasticity & SHM

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of

176 rad / s

. The frequency of this simple harmonic oscillator is___ Hz.

[

take

π = \frac{22}{7}]

Answer: (A)

In SHM, kinetic energy varies as

K E = \frac{1}{2} k A^{2} sin^{2} (ω t)

, which oscillates at frequency

2 ω

(since

sin^{2}

has double frequency). Given the KE oscillates at angular frequency 176 rad/s, the frequency of KE oscillation is

f_{K E} = \frac{176}{2 π} = \frac{176 \times 7}{2 \times 22} = 28

Hz. The oscillator's frequency is half of this:

f = \frac{f _{K E}}{2} = 14

Hz.

JEE Main · 2026 · 21 Jan 2026 · Shift 2 · Single correct option