JEE Main · 2023 · 10 Apr 2023 · Shift 2 · Elasticity & SHM

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A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s . The maximum force exerted by spring on block is ____ N.

Answer: 20

Solution

Given

T = 3.14 = π

s, we have

ω = \frac{2 π}{T} = \frac{2 π}{π} = 2

rad/s. The maximum force is

F_{m a x} = m a_{m a x} = m A ω^{2} = 5 \times 1 \times 2^{2} = 20

JEE Main · 2023 · 10 Apr 2023 · Shift 2 · Integer answer

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