JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Alternating Current

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Primary coil of a transformer is connected to 220 V ac. Primary and secondary turns of the transforms are 100 and 10 respectively. Secondary coil of transformer is connected to two series resistance shown in shown in figure. The output voltage (

V_{0}

) is :

(A)7 V✓ Correct
(B)15 V
(C)44 V
(D)22 V

Answer: (A)

Solution

Turns ratio gives the secondary emf:

ε_{2} = \frac{N _{2}}{N _{1}} ε_{1} = \frac{10}{100} (220) = 22 V

.

This 22 V drives current through the series 15 k

Ω

+ 7 k

Ω

combination:

i = \frac{22}{22 \times 1 0 ^{3}} = 1 mA

.

Output across the 7 k

Ω

resistor:

V_{0} = i R = (1 0^{- 3}) (7000) = 7 V

JEE Main · 2024 · 30 Jan 2024 · Shift 1 · Single correct option

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