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JEE Main · 2024 · 27 Jan 2024 · Shift 2 · Semiconductors

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The truth table of the given circuit diagram is :
  1. (A)A=0, B=0 → Y=1; A=0, B=1 → Y=0; A=1, B=0 → Y=0; A=1, B=1 → Y=1
  2. (B)A=0, B=0 → Y=0; A=0, B=1 → Y=1; A=1, B=0 → Y=1; A=1, B=1 → Y=0✓ Correct
  3. (C)A=0, B=0 → Y=0; A=0, B=1 → Y=0; A=1, B=0 → Y=0; A=1, B=1 → Y=1
  4. (D)A=0, B=0 → Y=1; A=0, B=1 → Y=1; A=1, B=0 → Y=1; A=1, B=1 → Y=0

Answer: (B)

Solution

Tracing the crossed wiring into the two AND gates, one AND gate receives and while the other receives and ; both outputs feed the final OR gate, giving

which is the exclusive-OR function. Evaluating all inputs: , , , .

JEE Main · 2024 · 27 Jan 2024 · Shift 2 · Single correct option

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