The correct truth table for the following logic circuit is :
(A)
A
B
Y
0
0
0
0
1
1
1
0
0
1
1
1
(B)
A
B
Y
0
0
1
0
1
1
1
0
0
1
1
1
✓ Correct
(C)
A
B
Y
0
0
1
0
1
1
1
0
0
1
1
0
(D)
A
B
Y
0
0
0
0
1
0
1
0
0
1
1
1
Answer: (B)
Solution
From the circuit, A passes through a NOT gate and is then combined with B in an OR gate: Y=Aˉ+B. A=0⇒Aˉ=1⇒Y=1 (rows 00, 01). A=1⇒Aˉ=0⇒Y=B: gives Y=0 for B=0 and Y=1 for B=1. This matches 00→1,01→1,10→0,11→1.
JEE Main · 2024 · 06 Apr 2024 · Shift 1 · Single correct option
