The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is
Answer: 5
Solution
3-bromo-3-cyclopentylhexane has the structure with Br at the tertiary carbon (C-3) bearing a cyclopentyl group and two ethyl groups.
Dehydrobromination can occur by removing H from adjacent carbons (C-2 or C-4), and also from the cyclopentyl ring.
Possible alkenes:
Total = 2 + 2 + 1 = 5 alkenes
Dehydrobromination can occur by removing H from adjacent carbons (C-2 or C-4), and also from the cyclopentyl ring.
Possible alkenes:
- From C-2: E and Z isomers (2 alkenes)
- From C-4: E and Z isomers (2 alkenes)
- From cyclopentyl ring: 1 alkene (exocyclic double bond)
Total = 2 + 2 + 1 = 5 alkenes
JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Integer answer