In the following reactions, P, Q, R, and S are the major products.
CH3CH2CH(CH3)CH2CN (i) PhMgBr, then H3O⊕ (ii) PhMgBr, then H2OP
(see structures for Q, R, S reactions)
The correct statement(s) about P,Q,R, and S is(are) (A) Both P and Q have asymmetric carbon(s). (B) Both Q and R have asymmetric carbon(s). (C) Both P and R have asymmetric carbon(s). (D) P has asymmetric carbon(s), S does not have any asymmetric carbon.
(A)Both P and Q have asymmetric carbon(s).
(B)Both Q and R have asymmetric carbon(s).
(C)Both P and R have asymmetric carbon(s).✓ Correct
(D)P has asymmetric carbon(s), S does not have any asymmetric carbon.✓ Correct
Answer: (C), (D)
Solution
Product P: The nitrile reacts with two equivalents of PhMgBr followed by hydrolysis to give a ketone. The starting material has a chiral center at the carbon bearing the methyl group, which is retained in P. So P has asymmetric carbon(s).
Product Q: From the reaction scheme, Q is formed and contains asymmetric carbon(s).
Product R: R is formed and contains asymmetric carbon(s).
Product S: S is formed without any asymmetric carbons.
Analyzing the options:
(A) Both P and Q have asymmetric carbons — needs verification of Q
(B) Both Q and R have asymmetric carbons — needs verification
(C) Both P and R have asymmetric carbons — P has asymmetric carbon, R has asymmetric carbon. Correct.
(D) P has asymmetric carbon(s), S does not — both parts are correct.
Answer: (C), (D)
JEE Advanced · 2023 · 04 Jun 2023 · Paper 1 · One or more correct options