JEE Main · 2026 · 04 Apr 2026 · Shift 1 · Semiconductors

Two 4 bits binary numbers, A=1101 and B=1010 are given in the inputs of a logic circuit shown in figure below. The output (Y) will be :

Answer: (A)

Solution

The inverter feeds

\overline{A}

into the NAND gate whose other input is

B

, so

Y = \overline{\overline{A} \cdot B}

, which by De Morgan's law is

Y = A + \overline{B}

. With

A = 1101

and

B = 1010

, the complement is

\overline{B} = 0101

. Taking the bitwise OR,

Y = 1101 + 0101 = 1101

JEE Main · 2026 · 04 Apr 2026 · Shift 1 · Single correct option