A particle of mass 0.3 kg is subjected to a force $\mathrm{F}=-\mathrm{kx}$ with $\mathrm{k}=15 \mathrm{~N} / \mathrm{m}$. What will be its initial acceleration if it is released from a point 20 cm away from the origin?

(D) $10 \mathrm{~m} / \mathrm{s}^{2}$

(A) $3 \mathrm{~m} / \mathrm{s}^{2}$

(B) $15 \mathrm{~m} / \mathrm{s}^{2}$

(C) $5 \mathrm{~m} / \mathrm{s}^{2}$

JEE Main · 2005 · 08 May 2005 · Offline · Elasticity & SHM

A particle of mass 0.3 kg is subjected to a force

F = - kx

with

k = 15 N / m

. What will be its initial acceleration if it is released from a point 20 cm away from the origin?

Answer: (D)

The force

F = k x

gives an acceleration

a = \frac{F}{m} = \frac{k x}{m}

at the instant of release. With

k = 15

N/m,

x = 0.2

m and

m = 0.3

kg,

a = \frac{15 \times 0.2}{0.3} = 10

m/s

^{2}

JEE Main · 2005 · 08 May 2005 · Offline · Single correct option