A transistor is connected in common emitter circuit configuration, then collector supply voltage is 10 V and the voltage drop across a resistor of $1000\Omega$ in the collector is 0.6 V. If the current gain factor $(\beta)$ is 24, then the base current is ______ $\mu\mathrm{A}$. (Round off to the Nearest Integer)

JEE Main · 2021 · 27 Jul 2021 · Shift 1 · Semiconductors

A transistor is connected in common emitter circuit configuration, then collector supply voltage is 10 V and the voltage drop across a resistor of

1000Ω

in the collector is 0.6 V. If the current gain factor

(β)

is 24, then the base current is ______

μ A

. (Round off to the Nearest Integer)

Answer: 25

The drop across the collector resistor fixes the collector current,

I_{C} = \frac{0.6}{1000} = 0.6 \times 1 0^{- 3} A = 600 μ A

In the common emitter configuration the current gain is

β = \frac{I _{C}}{I _{B}}

, so

I_{B} = \frac{600}{24} = 25

The base current is

25 μ

JEE Main · 2021 · 27 Jul 2021 · Shift 1 · Integer answer