JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Semiconductors

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A zener diode having zener voltage 8 V and power dissipation rating of 0.5 W is connected across a potential divider arranged with maximum potential drop across zener diode is as shown in the diagram. The value of protective resistance

R_{p}

is ______

Ω

Answer: 192

Solution

The potential divider is set for the maximum drop, so the whole supply of

20

V appears across

R_{p}

in series with the zener diode. The largest current the diode may carry follows from its power rating:

I_{Z} = \frac{P}{V _{Z}} = \frac{0.5}{8} = \frac{1}{16} A

The protective resistance carries this same current and takes up the remaining

20 - 8 = 12

V, so

R_{p} = \frac{12}{1/16}

The protective resistance is

192 Ω

JEE Main · 2021 · 20 Jul 2021 · Shift 2 · Integer answer

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