JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Semiconductors

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of

6 \times 1 0^{- 6} m

, will be ______

\times 1 0^{5} N / C

Answer: 1

Solution

The electric field intensity in the depletion region is given by

E = \frac{V}{d}

, where

V

is the potential barrier and

d

is the width of the depletion region. Substituting:

E = \frac{0.6}{6 \times 1 0 ^{- 6}} = 1 \times 1 0^{5} V/m = 1 \times 1 0^{5} N/C

JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Integer answer