JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Semiconductors

Find the modulation index of an AM wave having 8 V variation where maximum amplitude of the AM wave is 9 V .

Answer: (A)

Solution

The modulation index is

m = \frac{A _{m}}{A _{c}}

. Given that the variation is

2 A_{m} = 8 V

, so

A_{m} = 4 V

. The maximum amplitude is

A_{m} + A_{c} = 9 V

, so

A_{c} = 5 V

. Therefore,

m = \frac{4}{5} = 0.8

JEE Main · 2022 · 29 Jul 2022 · Shift 1 · Single correct option