For a series LCR circuit, I vs \(\omega\) curve is shown: (a) To the left of \(\omega_{r}\), the circuit is mainly capacitive. (b) To the left of \(\omega_{r}\), the circuit is mainly inductive. (c) At \(\omega_{r}\), impedance of the circuit is equal to the resistance of the circuit. (d) At \(\omega_{r}\), impedance of the circuit is 0. Choose the most appropriate answer from the options given below:

JEE Main · 2022 · 29 Jun 2022 · Shift 1 · Alternating Current

For a series LCR circuit, I vs

ω

curve is shown:
(a) To the left of

ω_{r}

, the circuit is mainly capacitive.
(b) To the left of

ω_{r}

, the circuit is mainly inductive.
(c) At

ω_{r}

, impedance of the circuit is equal to the resistance of the circuit.
(d) At

ω_{r}

, impedance of the circuit is 0.
Choose the most appropriate answer from the options given below:

Answer: (C)

At resonance (

ω_{r}

X_{C} = X_{L}

, so the impedance

Z = R

(statement c is correct). For

ω < ω_{r}

X_{C} = \frac{1}{ω C}

increases and

X_{L} = ω L

decreases, making

X_{C} > X_{L}

, so the circuit is capacitive (statement a is correct). Statement d is incorrect because impedance at resonance is R, not zero.

JEE Main · 2022 · 29 Jun 2022 · Shift 1 · Single correct option