Amplitude modulated wave is represented by $V_{\text {AM }}=10\left[1+0.4 \cos \left(2 \pi \times 10^{4} \mathrm{t}\right)\right] \cos \left(2 \pi \times 10^{7} \mathrm{t}\right)$. The total bandwidth of the amplitude modulated wave is:

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Semiconductors

Amplitude modulated wave is represented by

V_{AM} = 10 [1 + 0.4 cos (2 π \times 1 0^{4} t)] cos (2 π \times 1 0^{7} t)

.

The total bandwidth of the amplitude modulated wave is:

Answer: (C)

The general form of an AM wave is:

V_{A M} = A_{c} [1 + m cos (2 π f_{m} t)] cos (2 π f_{c} t)

where

f_{m}

is the modulating frequency and

f_{c}

is the carrier frequency.

From the given equation:

The bandwidth of an AM wave is:

Bandwidth = 2 f_{m} = 2 \times 1 0^{4} Hz = 20 kHz

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Single correct option