JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Semiconductors

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In AM modulation, a signal is modulated on a carrier wave such that maximum and minimum amplitude are found to be 6 V and 2 V respectively. The modulation index is

(A) $100%$
(B) $80%$
(C) $60%$
(D) $50%$ ✓ Correct

Answer: (D)

Solution

The modulation index is given by the formula:

μ = \frac{V _{max} - V _{min}}{V _{max} + V _{min}} \times 100%

Substituting the given values:

μ = \frac{6 - 2}{6 + 2} \times 100% = \frac{4}{8} \times 100% = 50%

Therefore, the modulation index is 50%.

JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Single correct option

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