JEE Main · 2023 · 29 Jan 2023 · Shift 2 · Alternating Current

In the first circuit the source drives current through a resistor alone, so the current is simply $\frac{V}{R}$. In the second circuit the same resistor is in series with an inductor and a capacitor, and the impedance $Z=\sqrt{R^2+(X_L-X_C{)}^2}$ is never smaller than $R$, dropping to $R$ only at resonance when $X_L=X_C$. Since the current is $\frac{V}{Z}$, the second circuit can at best match the first and can never carry a larger rms current than the purely resistive one.