A mass m is attached to two springs as shown in figure. The spring constants of two springs are K1 and K2. For the frictionless surface, the time period of oscillation of mass m is
(A)2π1mK1+K2
(B)2π1mK1−K2
(C)2πK1+K2m✓ Correct
(D)2πK1−K2m
Answer: (C)
Solution
When the mass is displaced by distance x to the right, both springs exert restoring forces toward equilibrium.
Net force: F=−(k1x+k2x)=−(k1+k2)x
Acceleration: a=mF=−mk1+k2x=−ω2x
Angular frequency: ω=mk1+k2
Time period: T=ω2π=2πk1+k2m
JEE Main · 2023 · 06 Apr 2023 · Shift 1 · Single correct option