For compound having the formula $\mathrm{GaAlCl}_{4}$, the correct option from the following is

(A) Ga is more electronegative than Al and is present as a cationic part of the salt $\mathrm{GaAlCl}_{4}$

(B) Oxidation state of Ga in the salt $\mathrm{GaAlCl}_{4}$ is +3 .

(C) Cl forms bond with both Al and Ga in $\mathrm{GaAlCl}_{4}$

(D) Ga is coordinated with Cl in $\mathrm{GaAlCl}_{4}$

JEE Main · 2023 · 11 Apr 2023 · Shift 1 · p-Block Elements

For compound having the formula

GaAlCl_{4}

, the correct option from the following is

(A)Ga is more electronegative than Al and is present as a cationic part of the salt $GaAlCl_{4}$ ✓ Correct
(B)Oxidation state of Ga in the salt $GaAlCl_{4}$ is +3 .
(C)Cl forms bond with both Al and Ga in $GaAlCl_{4}$
(D)Ga is coordinated with Cl in $GaAlCl_{4}$

Answer: (A)

Solution

The formula

GaAlCl X_{4}

is the ionic salt

Ga X^{+} [AlCl X_{4}] X^{-}

: gallium is in the +1 state as the cation, while aluminium occupies the tetrahedral

[AlCl X_{4}] X^{-}

anion where the chlorines are bonded only to aluminium, not to gallium. Owing to the d-block contraction gallium is in fact slightly more electronegative than aluminium

(χ_{G a} = 1.81, χ_{A l} = 1.61)

, yet it is gallium that forms the cationic part. Thus gallium is more electronegative than aluminium and is present as the cationic part of the salt.

JEE Main · 2023 · 11 Apr 2023 · Shift 1 · Single correct option

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JEE Main · 2023 · 11 Apr 2023 · Shift 1 · p-Block Elements

Solution

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