Given below are two statements :
Statement I: The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.
Statement II : A group 15 element's hydride has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4 .
In the light of the above statements, choose the correct answer from the options given below.
Statement I: The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.
Statement II : A group 15 element's hydride has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4 .
In the light of the above statements, choose the correct answer from the options given below.
- (A)Both Statement I and Statement II are true.
- (B)Statement I is false but Statement II is true.
- (C)Both Statement I and Statement II are false.✓ Correct
- (D)Statement I is true but Statement II is false.
Answer: (C)
Solution
The hydrogen-halogen bond length increases down the group as , so the longest bond, that in HI, is made with iodine, the halogen of largest covalent radius, not the smallest; Statement I is false. Among the group 15 hydrides the boiling points run , so has the lowest boiling point; but phosphorus can expand its valence shell to a maximum covalency of six, as in , not four, so Statement II is also false. Both statements are false.
JEE Main · 2026 · 22 Jan 2026 · Shift 1 · Single correct option