JEE Main · 2023 · 06 Apr 2023 · Shift 1 · p-Block Elements

Answer: A → III, B → I, C → II, D → IV

Solution

Each oxide is matched by the characteristic linkage in its structure.

N_{2} O_{4}

O_{2} N - NO_{2}

, joined by a single

N - N

bond.

NO_{2}

is a bent radical carrying one

N = O

double bond.

N_{2} O_{5}

O_{2} N - O - NO_{2}

, with an

N - O - N

bridge.

N_{2} O

N \equiv N - O

, containing a nitrogen-nitrogen multiple bond. The correct pairing is

N_{2} O_{4}

with the

N - N

bond,

NO_{2}

with the

N = O

bond,

N_{2} O_{5}

with the

N - O - N

bond, and

N_{2} O

with the nitrogen-nitrogen multiple bond.

JEE Main · 2023 · 06 Apr 2023 · Shift 1 · Match the columns