JEE Main · 2025 · 07 Apr 2025 · Shift 2 · Hydrocarbons

The number of optically active products obtained from the complete ozonolysis of the given compound is :

(A)2
(B)0✓ Correct
(C)1
(D)4

Answer: (B)

Solution

Complete ozonolysis cuts every carbon-carbon double bond and caps each severed carbon with oxygen as a carbonyl. The chain carries three double bonds, and cleaving all of them breaks the molecule exactly at the bonds flanking each of the two substituted carbons. After cleavage those carbons each end up bonded to two identical formyl groups along with a methyl and a hydrogen, so neither keeps four different groups and neither remains a stereocentre. The fragments are ethanal and 2-methylpropanedial, every one of them achiral, so the number of optically active products is zero.

JEE Main · 2025 · 07 Apr 2025 · Shift 2 · Single correct option

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