JEE Main · 2026 · 23 Jan 2026 · Shift 1 · Hydrocarbons

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But-2-yne and hydrogen (one mole each) are separately treated with (i) and (ii) liq. to give the products X and Y respectively.

Identify the incorrect statements.
A. and are stereoisomers.
B. Dipole moment of X is zero
C. Boiling point of X is higher than Y .
D. X and Y react with to give different products.
Choose the correct answer from the options given below:
  1. (A)B and C only
  2. (B)B and D only✓ Correct
  3. (C)A and B only
  4. (D)A and C only

Answer: (B)

Solution

But-2-yne takes up one mole of hydrogen over palladium on carbon by syn addition to give cis-but-2-ene (X), while dissolving-metal reduction with sodium in liquid ammonia proceeds by anti addition to give trans-but-2-ene (Y); the two are cis-trans stereoisomers, so statement A is true. The cis isomer carries its methyl groups on the same side and has a small but non-zero dipole moment, whereas only the trans isomer is non-polar, so the claim that X has zero dipole moment is wrong. Being more polar, the cis isomer has the higher boiling point, so statement C is true. Reductive ozonolysis of either but-2-ene cleaves the same internal double bond to give acetaldehyde from both, so the claim that they give different products is wrong. The incorrect statements are B and D.

JEE Main · 2026 · 23 Jan 2026 · Shift 1 · Single correct option

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