Choose the correct statements from the following A. All group 16 elements form oxides of general formula
EO2
and
EO3
where
E=S,Se,Te
and Po. Both the types of oxides are acidic in nature. B.
TeO2
is an oxidising agent while
SO2
is reducing in nature. C. The reducing property decreases from
H2S
to
H2Te
down the group. D. The ozone molecule contains five lone pairs of electrons. Choose the correct answer from the options given below:
(A)A and D only
(B)B and C only
(C)C and D only
(D)A and B only✓ Correct
Answer: (D)
Solution
A: all Group 16 elements S, Se, Te and Po form EO2 and EO3 type oxides, and both types are acidic in nature — true.
B: SO2 has sulfur in the +4 state, which is readily oxidized to +6, so SO2 acts as a reducing agent; TeO2, with the heavier, more metallic tellurium, instead acts as an oxidizing agent — true.
C: down Group 16, the H–E bond becomes progressively weaker, making the hydride release H+/electrons more easily, so reducing power actually increases from H2S to H2Te, not decreases — false.
D: ozone is a bent, resonance-stabilized molecule; a full Lewis structure accounting for both resonance forms places two lone pairs on each terminal oxygen plus one lone pair on the central oxygen, giving six lone pairs in total, not five — false.
Only A and B are correct.Ozone structure
JEE Main · 2024 · 31 Jan 2024 · Shift 2 · Single correct option