Match List - I with List - II. List - I: Isomers of $\mathrm{C}_{10}\mathrm{H}_{14}$ List - II: Ozonolysis product Choose the correct answer from the options given below:

JEE Main · 2025 · 23 Jan 2025 · Shift 2 · Hydrocarbons

Match List - I with List - II.

List - I: Isomers of

C_{10} H_{14}

List - II: Ozonolysis product

Choose the correct answer from the options given below:

Answer: A → III, B → IV, C → I, D → II

Solution

Ozonolysis cleaves each

C = C

double bond of these bicyclic

C X_{10} H X_{14}

isomers, replacing it with two carbonyl groups positioned exactly where the double bond sat. Tracing the double-bond position in each isomer through to the resulting diketone/dialdehyde fragment gives the matching (A)–(III), (B)–(IV), (C)–(I), (D)–(II).

JEE Main · 2025 · 23 Jan 2025 · Shift 2 · Match the columns

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