9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is ____ %.
Answer: 80
Solution
Aniline reacts with bromine water to give 2,4,6-tribromoaniline (white ppt). Stoichiometry: 93 g aniline (1 mol) gives 330 g tribromoaniline (1 mol). So 9.3 g aniline should give 33 g theoretically.