In the following reaction, the product(s) formed is(are)
(A)P (major)
(B)Q (minor)✓ Correct
(C)R (minor)
(D)S (major)✓ Correct
Answer: (B), (D)
Solution
The reaction involves Friedel-Crafts acylation followed by intramolecular cyclization. The major product S is formed via the favored 6-membered ring closure. The minor product Q results from an alternative cyclization pathway. Products P and R are not formed under these conditions.
JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · One or more correct options