JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Aldehydes Ketones and Carboxylic Acids

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The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct options.

List-I
(P) Stephen reaction
(Q) Sandmeyer reaction
(R) Hoffmann bromamide degradation reaction
(S) Cannizzaro reaction

List-II
(1) (see structure)
(2) (see structure)
(3) (see structure)
(4) (see structure)
(5) (see structure)

(A) $P \to 2; Q \to 4; R \to 1; S \to 3$
(B) $P \to 2; Q \to 3; R \to 4; S \to 1$ ✓ Correct
(C) $P \to 5; Q \to 3; R \to 4; S \to 2$
(D) $P \to 5; Q \to 4; R \to 2; S \to 1$

Answer: (B)

Solution

Matching named reactions with their starting materials:

(P) Stephen reaction requires a nitrile (R-CN) to form an aldehyde → (2) benzonitrile

(Q) Sandmeyer reaction requires an aryl diazonium salt to form aryl halides/cyanides → (3) benzenediazonium chloride

(R) Hoffmann bromamide degradation requires a primary amide to form an amine with one less carbon → (4) benzamide

(S) Cannizzaro reaction requires an aldehyde without α-hydrogen (like benzaldehyde) → (1) benzaldehyde

Therefore, P→2; Q→3; R→4; S→1

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JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Aldehydes Ketones and Carboxylic Acids

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