JEE Advanced · 2022 · 28 Aug 2022 · Paper 2 · Practical and Analytical Chemistry

The reaction

Pb (NO_{3})_{2}

and NaCl in water produces a precipitate that dissolves upon the addition of HCl of appropriate concentration. The dissolution of the precipitate is due to the formation of

(A) $PbCl_{2}$
(B) $PbCl_{4}$
(C) $[PbCl_{4}]^{2 -}$ ✓ Correct
(D) $[PbCl_{6}]^{2 -}$

Answer: (C)

Solution

Pb (NO_{3})_{2}

reacts with NaCl to form

PbCl_{2}

precipitate:

Pb (NO_{3})_{2} + 2 NaCl \to PbCl_{2} ↓ + 2 NaNO_{3}

When excess HCl is added,

PbCl_{2}

dissolves by forming a soluble complex:

PbCl_{2} + 2 Cl^{-} \to [PbCl_{4}]^{2 -}

The complex ion

[PbCl_{4}]^{2 -}

is soluble in water.

JEE Advanced · 2022 · 28 Aug 2022 · Paper 2 · Single correct option

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