The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is | List-I | List-II | |--------|--------| | (P) Passing $\mathrm{H}_{2} \mathrm{~S}$ in the presence of $\mathrm{NH}_{4} \mathrm{OH}$ | (1) $\mathrm{Cu}^{2+}$ | | (Q) $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}$ in the presence of $\mathrm{NH}_{4} \mathrm{OH}$ | (2) $\mathrm{Al}^{3+}$ | | (R) $\mathrm{NH}_{4} \mathrm{OH}$ in the presence of $\mathrm{NH}_{4} \mathrm{Cl}$ | (3) $\mathrm{Mn}^{2+}$ | | (S) Passing $\mathrm{H}_{2} \mathrm{~S}$ in the presence of dilute HCl | (4) $\mathrm{Ba}^{2+}$ | | | (5) $\mathrm{Mg}^{2+}$ |

(A) $\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 1$

(B) $\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 1$

(C) $\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 5$

(D) $\mathrm{P} \rightarrow 5 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 4$

JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Practical and Analytical Chemistry

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List-I	List-II
(P) Passing $H_{2} S$ in the presence of $NH_{4} OH$	(1) $Cu^{2 +}$
(Q) $(NH_{4})_{2} CO_{3}$ in the presence of $NH_{4} OH$	(2) $Al^{3 +}$
(R) $NH_{4} OH$ in the presence of $NH_{4} Cl$	(3) $Mn^{2 +}$
(S) Passing $H_{2} S$ in the presence of dilute HCl	(4) $Ba^{2 +}$
	(5) $Mg^{2 +}$

Answer: (A)

Matching the group reagents with metal ions:

(P)

H_{2} S

in presence of

NH_{4} OH

(basic medium) precipitates Group IV cations like

Mn^{2 +}

as pink/buff

MnS

→ (3)

(Q)

(NH_{4})_{2} CO_{3}

in presence of

NH_{4} OH

precipitates Group V cations like

Ba^{2 +}

BaCO_{3}

→ (4)

(R)

NH_{4} OH

in presence of

NH_{4} Cl

precipitates Group III cations like

Al^{3 +}

Al (OH)_{3}

→ (2)

(S)

H_{2} S

in presence of dilute HCl (acidic medium) precipitates Group II cations like

Cu^{2 +}

CuS

→ (1)

Therefore, P→3; Q→4; R→2; S→1

JEE Advanced · 2025 · 18 May 2025 · Paper 1 · Single correct option