JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Practical and Analytical Chemistry

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Match the compounds in LIST-I with the observation in LIST-II, and choose the correct option.
LIST-ILIST-II
(I) Aniline(P) Sodium fusion extract of the compound on boiling with , followed by acidification with conc. , gives Prussian blue color.
(II) o-Cresol(Q) Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
(III) Cysteine(R) Addition of the compound to a saturated solution of results in effervescence.
(IV) Coprolactam(S) The compound reacts with bromine water to give a white precipitate.
(T) Treating the compound with neutral solution produces violet color.
  1. (A)I → P, Q; II → S; III → Q, R; IV → P
  2. (B)I → P; II → R, S; III → R; IV → Q, S
  3. (C)I → Q, S; II → P, T; III → P; IV → S
  4. (D)I → P, S; II → T; III → Q, R; IV → P✓ Correct

Answer: (D)

Solution

Matching each compound with observations:

(I) Aniline ():
  • Contains nitrogen → gives Prussian blue in Lassaigne's test (P)
  • Reacts with bromine water to give white precipitate of 2,4,6-tribromoaniline (S)

(II) o-Cresol (methylphenol):
  • Phenolic OH gives violet color with neutral (T)

(III) Cysteine (amino acid with -SH group):
  • Contains sulfur → gives blood red color with sodium nitroprusside (Q)
  • Carboxylic acid group reacts with to give effervescence (R)

(IV) Caprolactam (cyclic amide):
  • Contains nitrogen → gives Prussian blue in Lassaigne's test (P)

Therefore, option (D): I → P, S; II → T; III → Q, R; IV → P is correct.

JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Single correct option

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