An alkene (X) on ozonolysis followed by reduction gives following products.
2 moles of formaldehyde, glyoxal, and methylglyoxal.
The alkene ( X ) is :
(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)✓ Correct
Answer: (D)
Solution
Reductive ozonolysis cleaves every carbon--carbon double bond into two carbonyl groups. Reading back from the products, the two molecules of methanal arise from two exocyclic =CHX2 groups; the fragment OHC−CO−CHO arises from three consecutive ring carbons whose central carbon carried an exocyclic methylene and whose outer two were ring =CH− carbons; and the fragment CHX3−CO−CO−CO−CHX3 arises from three consecutive ring carbons whose central carbon carried an exocyclic methylene and whose outer two were methyl-bearing ring =C(CHX3)− carbons. Rejoining these pieces at the cleaved double bonds reproduces a cyclohexa-1,4-diene that bears a methyl group on each of the two double-bond carbons of one fragment and an exocyclic =CHX2 on each of the two ring carbons that become ketonic; this is the structure of alkene X.
JEE Main · 2026 · 04 Apr 2026 · Shift 1 · Single correct option