JEE Main · 2017 · 02 Apr 2017 · Offline · p-Block Elements

The products obtained when chlorine gas reacts with hot and concentrated NaOH are:

(A)ClO⁻ and ClO₃⁻
(B)Cl⁻ and ClO₃⁻✓ Correct
(C)Cl⁻ and ClO⁻
(D)ClO₂⁻ and ClO₃⁻

Answer: (B)

Solution

Hot concentrated NaOH drives disproportionation of chlorine:

3 C l_{2} + 6 O H^{-} \to 5 C l^{-} + Cl O_{3}^{-} + 3 H_{2} O

. Chlorine (0) is split into

- 1

(

C l^{-}

) and

+ 5

(

Cl O_{3}^{-}

). Cold dilute NaOH would instead give

C l^{-}

and

Cl O^{-}

JEE Main · 2017 · 02 Apr 2017 · Offline · Single correct option

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