If a straight line passing through the point P(−3,4) is such that its intercepted portion between the coordinate axes is bisected at P , then its equation is:
(A)3x−4y+25=0
(B)4x−3y+24=0✓ Correct
(C)x−y+7=0
(D)4x+3y=0
Answer: (B)
Solution
If the segment cut off between the axes is bisected at P(−3,4), and the intercepts are (a,0) and (0,b), their midpoint (2a,2b) equals (−3,4), so a=−6 and b=8. The line −6x+8y=1 clears to 4x−3y+24=0.
JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option