A rectangle is formed by the lines x=0, y=0, x=3 and y=4. Let the line L be perpendicular to 3x+y+6=0 and divide the area of the rectangle into two equal parts. Then the distance of the point (21,−5) from the line L is equal to :
(A)25
(B)310
(C)10
(D)210✓ Correct
Answer: (D)
Solution
The line perpendicular to 3x+y+6=0 has slope 31, so its equation is y=3x+c.
To divide the rectangle into two equal parts, the line must pass through the center (23,2).
Substituting: 2=21+c, so c=23.
The line is y=3x+23, or 2x−6y+9=0.
Distance from (21,−5): d=4+36∣2(21)−6(−5)+9∣=40∣1+30+9∣=21040=210.
JEE Main · 2026 · 23 Jan 2026 · Shift 1 · Single correct option