JEE Main · 2020 · 06 Sep 2020 · Shift 2 · p-Block Elements

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Reaction of an inorganic sulphite X with dilute H₂SO₄ generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound Z. Y and Z respectively, are:

(A)SO₂ and Na₂SO₃
(B)SO₃ and NaHSO₃
(C)SO₂ and NaHSO₃✓ Correct
(D)S and Na₂SO₃

Answer: (C)

Solution

Trace the sulphur chemistry. Sodium sulphite

X

with dilute

H X_{2} SO X_{4}

liberates sulphur dioxide,

Na X_{2} SO X_{3} + H X_{2} SO X_{4} SO X_{2} + Na X_{2} SO X_{4} + H X_{2} O

, so

Y

SO X_{2}

. With sodium hydroxide this gas regenerates the sulphite,

SO X_{2} + 2 NaOH Na X_{2} SO X_{3} + H X_{2} O

, recovering

X

. Finally the sulphite, the gas and water give the hydrogensulphite,

Na X_{2} SO X_{3} + SO X_{2} + H X_{2} O 2 NaHSO X_{3}

, so

Z

NaHSO X_{3}

. Hence

Y

SO X_{2}

and

Z

NaHSO X_{3}

JEE Main · 2020 · 06 Sep 2020 · Shift 2 · Single correct option

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JEE Main · 2020 · 06 Sep 2020 · Shift 2 · p-Block Elements

Solution

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