Reaction of ammonia with excess $\mathrm{Cl}_{2}$ gives:

(A) $\mathrm{NCl}_{3}$ and HCl

(B) $\mathrm{NCl}_{3}$ and $\mathrm{NH}_{4} \mathrm{Cl}$

(C) $\mathrm{NH}_{4} \mathrm{Cl}$ and $\mathrm{N}_{2}$

(D) $\mathrm{NH}_{4} \mathrm{Cl}$ and HCl

JEE Main · 2020 · 05 Sep 2020 · Shift 2 · p-Block Elements

Reaction of ammonia with excess

Cl_{2}

gives:

(A) $NCl_{3}$ and HCl✓ Correct
(B) $NCl_{3}$ and $NH_{4} Cl$
(C) $NH_{4} Cl$ and $N_{2}$
(D) $NH_{4} Cl$ and HCl

Answer: (A)

Solution

With chlorine in excess, every

N - H

bond of ammonia is attacked and all three hydrogens are replaced, giving the explosive nitrogen trichloride together with hydrogen chloride:

NH X_{3} + 3 Cl X_{2} NCl X_{3} + 3 HCl

. Had ammonia instead been in excess, the products would have been ammonium chloride and nitrogen.

JEE Main · 2020 · 05 Sep 2020 · Shift 2 · Single correct option

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