The major product [B] in the following sequence is:
(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)✓ Correct
Answer: (D)
Solution
Hydroboration-oxidation with BHX3 then HX2OX2/OHX− adds water across the double bond with anti-Markovnikov orientation, placing the −OH on the less substituted carbon. PBrX3 then swaps that −OH for bromine, and the bulky base potassium tert-butoxide forces an E2 elimination. Because the base removes a hydrogen to give the more substituted, Zaitsev alkene, the sequence returns the more highly substituted alkene as the major product.
JEE Main · 2020 · 08 Jan 2020 · Shift 2 · Single correct option