Match List-I with List-II: List-I (Species) List-II (Number of lone pairs of electrons on the central atom) (a) $\mathrm{XeF}_{2}$ (b) $\mathrm{XeO}_{2}\mathrm{~F}_{2}$ (c) $\mathrm{XeO}_{3}\mathrm{~F}_{2}$ (d) $\mathrm{XeF}_{4}$ (i) 0 (ii) 1 (iii) 2 (iv) 3 Choose the most appropriate answer from the options given below:

Counting lone pairs on xenon from its eight valence electrons: in two electrons form the two bonds, leaving three lone pairs. In the two and two linkages use six electrons, leaving one lone pair. In three and two linkages use all eight electrons, leaving no lone pair. In four bonds use four electro…

JEE Main · 2021 · 27 Aug 2021 · Shift 1 · p-Block Elements

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Match List-I with List-II:
List-I (Species)
List-II (Number of lone pairs of electrons on the central atom)
(a)

XeF_{2}

(b)

XeO_{2} F_{2}

(c)

XeO_{3} F_{2}

(d)

XeF_{4}

(i) 0
(ii) 1
(iii) 2
(iv) 3
Choose the most appropriate answer from the options given below:

Answer: A → IV, B → II, C → I, D → III

Solution

Counting lone pairs on xenon from its eight valence electrons: in

Xe F_{2}

two electrons form the two

Xe - F

bonds, leaving three lone pairs. In

Xe O_{2} F_{2}

the two

Xe = O

and two

Xe - F

linkages use six electrons, leaving one lone pair. In

Xe O_{3} F_{2}

three

Xe = O

and two

Xe - F

linkages use all eight electrons, leaving no lone pair. In

Xe F_{4}

four bonds use four electrons, leaving two lone pairs. So

Xe F_{2}

has three,

Xe O_{2} F_{2}

one,

Xe O_{3} F_{2}

zero and

Xe F_{4}

two lone pairs.

JEE Main · 2021 · 27 Aug 2021 · Shift 1 · Match the columns

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JEE Main · 2021 · 27 Aug 2021 · Shift 1 · p-Block Elements

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