Among the given oxides of nitrogen; \(\mathrm{N}_{2} \mathrm{O}, \mathrm{N}_{2} \mathrm{O}_{3}\), \(\mathrm{N}_{2} \mathrm{O}_{4}\) and \(\mathrm{N}_{2} \mathrm{O}_{5}\), the number of compound/(s) having \(\mathrm{N}-\mathrm{N}\) bond is :

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · p-Block Elements

Among the given oxides of nitrogen;

N_{2} O, N_{2} O_{3}

N_{2} O_{4}

and

N_{2} O_{5}

, the number of compound/(s) having

N - N

bond is :

Answer: (C)

Writing out the structures settles the count. Nitrous oxide

N_{2} O

is arranged as

N - N - O

(the hybrid of

N \equiv N - O

and

N = N = O

), so a nitrogen-nitrogen bond is present. Dinitrogen trioxide

N_{2} O_{3}

is the anhydride of nitrous acid with structure

O = N - N O_{2}

, a nitroso group joined directly to a nitro group, so it too has an

N - N

bond. In

N_{2} O_{4}

the two

N O_{2}

units are linked as

O_{2} N - N O_{2}

, again an

N - N

bond. Only in

N_{2} O_{5}

, which is

O_{2} N - O - N O_{2}

, are the nitrogen atoms joined through an oxygen bridge and no

N - N

bond exists. Thus three of the four oxides contain an

N - N

bond.

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Single correct option