The sum of number of lone pairs of electrons present on the central atoms of $\mathrm{XeO}_{3}$, $\mathrm{XeOF}_{4}$ and $\mathrm{XeF}_{6}$ is \_\_\_\_

JEE Main · 2022 · 25 Jul 2022 · Shift 2 · p-Block Elements

The sum of number of lone pairs of electrons present on the central atoms of

XeO_{3}

XeOF_{4}

and

XeF_{6}

is ____

Answer: 3

Solution

For

XeO_{3}

: Xe has 8 valence electrons, forms 3 double bonds with O (using 6 electrons), leaving 1 lone pair.

For

XeOF_{4}

: Xe has 8 valence electrons, forms 1 double bond with O and 4 single bonds with F (using 6 electrons), leaving 1 lone pair.

For

XeF_{6}

: Xe has 8 valence electrons, forms 6 single bonds with F (using 6 electrons), leaving 1 lone pair.

Total = 1 + 1 + 1 = 3.

Structure XeO3 structure — XeO3 structure

Structure XeOF4 structure — XeOF4 structure

Structure XeF6 structure — XeF6 structure

JEE Main · 2022 · 25 Jul 2022 · Shift 2 · Integer answer

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