When a 60 W electric heater is immersed in a gas for 100s in a constant volume container with adiabatic walls, the temperature of the gas rises by . The heat capacity of the given gas is ______ J K (Nearest integer)
Answer: 1200
Solution
Power of heater = 60 W = 60 J/s
Total energy supplied = Power × time = 60 J/s × 100 s = 6000 J
Since the container has adiabatic walls, all the energy goes into heating the gas (no heat loss to surroundings).
Heat capacity × Temperature change = Energy supplied
Heat capacity = = 1200 J K⁻¹
Total energy supplied = Power × time = 60 J/s × 100 s = 6000 J
Since the container has adiabatic walls, all the energy goes into heating the gas (no heat loss to surroundings).
Heat capacity × Temperature change = Energy supplied
Heat capacity = = 1200 J K⁻¹
JEE Main · 2023 · 08 Apr 2023 · Shift 1 · Integer answer