JEE Main · 2023 · 06 Apr 2023 · Shift 2 · Laws of Motion

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A child of mass 5 kg is going round a merry-go-round that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be

(A)80 N
(B)50 N
(C)100 N
(D)40 N✓ Correct

Answer: (D)

Solution

One rotation in

T = 3.14

s gives an angular speed

ω = \frac{2 π}{T} = 2

rad s

^{- 1}

. In the rotating frame the child of mass

m = 5

kg at radius

R = 2

m experiences a centrifugal force

F = m ω^{2} R = 5 \times 2^{2} \times 2

. The centrifugal force on the child is

40

JEE Main · 2023 · 06 Apr 2023 · Shift 2 · Single correct option

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