The correct IUPAC nomenclature for the following compound is
(A)5-Formyl-2-methylhexanoic acid
(B)2-Methyl-5-oxohexanoic acid✓ Correct
(C)2-Formyl-5-methylhexan-6-oic acid
(D)5-Methyl-2-oxohexan-6-oic acid
Answer: (B)
Solution
The carboxylic acid group has the highest priority and is given position one, so the main chain is numbered from that carbon. The longest chain carrying the acid group contains six carbons, making it a hexanoic acid. A methyl group is attached at carbon two, and the ketonic oxygen, named as the prefix oxo, is at carbon five. The compound is therefore 2-methyl-5-oxohexanoic acid.
JEE Main · 2023 · 08 Apr 2023 · Shift 2 · Single correct option