JEE Main · 2026 · 28 Jan 2026 · Shift 2 · Chemical Thermodynamics

The plot of

lo g_{10} K

\frac{1}{T}

gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).

Answer: (B)

Solution

The temperature dependence of the equilibrium constant is

lo g_{10} K = - \frac{Δ H ^{\circ}}{2.303 R T} + \frac{Δ S ^{\circ}}{2.303 R}

. Read as a straight line of

lo g_{10} K

against

\frac{1}{T}

, the temperature-independent term is the intercept and the coefficient of

\frac{1}{T}

is the slope. The intercept is

\frac{Δ S ^{\circ}}{2.303 R}

and the slope is

- \frac{Δ H ^{\circ}}{2.303 R}

JEE Main · 2026 · 28 Jan 2026 · Shift 2 · Single correct option