Given below are two statements:
Statement I: is more stable than as nine hyperconjugation interactions are possible in .
Statement II: is less stable than as only three hyperconjugation interactions are possible in .
In the light of the above statements, choose the correct answer from the options given below.
Statement I: is more stable than as nine hyperconjugation interactions are possible in .
Statement II: is less stable than as only three hyperconjugation interactions are possible in .
In the light of the above statements, choose the correct answer from the options given below.
- (A)Statement I is true but Statement II is false✓ Correct
- (B)Both Statement I and Statement II are true
- (C)Both Statement I and Statement II are false
- (D)Statement I is false but Statement II is true
Answer: (A)
Solution
In each of the three methyl groups offers three C--H bonds that can overlap with the empty orbital, giving nine hyperconjugative interactions that make it far more stable than , so the first statement is sound. The methyl cation has its three C--H bonds on the cationic carbon itself and no adjacent () C--H bonds, so it has zero hyperconjugative interactions, not three, which makes the second statement wrong. The first statement is true and the second is false.
JEE Main · 2026 · 23 Jan 2026 · Shift 2 · Single correct option