JEE Main · 2024 · 30 Jan 2024 · Shift 2 · General Organic Chemistry

Number of geometrical isomers possible for the given structure is/are ____.

Answer: 4

Solution

The structure has three C=C double bonds, each of which can independently adopt E or Z configuration, giving up to

2^{3} = 8

combinations. Because two of the three double bonds sit in an identical structural environment (the chain is symmetric about the central alkene), several of these eight combinations coincide with one another on reflection, collapsing to four genuinely distinct geometrical isomers: (E,E,E), (Z,Z,Z), (E,Z,E) and (Z,E,Z). Four geometrical isomers are possible for the given structure.

JEE Main · 2024 · 30 Jan 2024 · Shift 2 · Integer answer

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