JEE Main · 2024 · 29 Jan 2024 · Shift 2 · Compounds Containing Nitrogen

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Which of the following reaction is correct ?
  1. (A)(see structure)
  2. (B)(see structure)
    ✓ Correct
  3. (C)(see structure)
  4. (D)(see structure)

Answer: (B)

Solution

Addition of HI to 4-methylcyclohex-1-ene follows Markovnikov's rule: protonation of the double bond generates the more stable (more substituted) carbocation at the ring carbon best able to stabilise positive charge, and iodide ion then attacks this carbon, giving 1-iodo-4-methylcyclohexane.

The other proposed reactions do not hold up. Treating a primary aliphatic amine with in water liberates and gives the corresponding alcohol with water as the only other product — not HCl. Photochemical bromination under UV light proceeds by a free-radical chain substitution at a C–H bond, not the vicinal-addition product shown. Hofmann bromamide degradation of (propanamide) removes the carbonyl carbon as carbonate, so the resulting amine has one carbon fewer than the amide; the product written retains all three carbons, which the reaction does not give.

The Markovnikov addition of HI to 4-methylcyclohex-1-ene is the correct reaction.

JEE Main · 2024 · 29 Jan 2024 · Shift 2 · Single correct option

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