An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with \(\mathrm{Br}_{2}\) and KOH forms compound (R) having molecular formula \(\mathrm{C}_{7} \mathrm{H}_{9} \mathrm{~N}\). Names of \(\mathrm{P}, \mathrm{Q}\) and R respectively are.

(D) Phenylethanoic acid, phenylethanamide, benzamine

(A) Benzoic acid, benzamide, aniline

(B) Toluic acid, methylbenzamide, 2-methylaniline

(C) Benzoic acid, 4-methylbenzamide, 4-methylaniline.

JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Compounds Containing Nitrogen

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with

Br_{2}

and KOH forms compound (R) having molecular formula

C_{7} H_{9} N

. Names of

P, Q

and R respectively are.

(A)Benzoic acid, benzamide, aniline
(B)Toluic acid, methylbenzamide, 2-methylaniline
(C)Benzoic acid, 4-methylbenzamide, 4-methylaniline.
(D)Phenylethanoic acid, phenylethanamide, benzamine✓ Correct

Answer: (D)

Solution

The amine R has the formula C

_{7}

_{9}

N (benzylamine). Working back, R is formed from the amide Q by the Hofmann bromamide reaction with Br

_{2}

and KOH, which removes one carbon, so Q has eight carbons; Q in turn comes from the acid P on heating with aqueous ammonia. Taking P as phenylethanoic acid, C

_{6}

_{5}

_{2}

COOH, makes Q the amide phenylethanamide, C

_{6}

_{5}

_{2}

CONH

_{2}

, and Hofmann degradation then gives R as benzylamine, C

_{6}

_{5}

_{2}

_{2}

. P, Q and R are phenylethanoic acid, phenylethanamide and benzylamine respectively.

JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Single correct option

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JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Compounds Containing Nitrogen

Solution

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